The area that lies between $$ z=-1.57 $$ and $$ z=-2.07 $$ is (Round to four decimal places as needed.)

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Let the area $$ A $$ between $$ z = -2.07 $$ and $$ z = -1.57 $$ be given by

$$
A = P(-2.07 \leq z \leq -1.57) = \Phi(-1.57) - \Phi(-2.07)
$$

where $$ \Phi(z) $$ is the cumulative distribution function (CDF) of the standard normal distribution.

Using the symmetry of the normal distribution, we know

$$
\Phi(-x) = 1 - \Phi(x)
$$

Thus,

$$
\Phi(-1.57) = 1 - \Phi(1.57) \quad \text{and} \quad \Phi(-2.07) = 1 - \Phi(2.07)
$$

Suppose from the standard normal table we have:

$$
\Phi(1.57) \approx 0.9418 \quad \text{and} \quad \Phi(2.07) \approx 0.9808
$$

Then,

$$
\Phi(-1.57) \approx 1 - 0.9418 = 0.0582
$$
$$
\Phi(-2.07) \approx 1 - 0.9808 = 0.0192
$$

Now, the area is

$$
A \approx 0.0582 - 0.0192 = 0.0390
$$

Thus, the area that lies between $$ z = -1.57 $$ and $$ z = -2.07 $$ is approximately $$ 0.0390 $$.
The area between $$ z = -1.57 $$ and $$ z = -2.07 $$ is approximately 0.0390.

The area that lies between and is
(Round to four decimal places as needed.)

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The area that lies between and is (Round to four decimal places as needed.)