Find the domain of the function. $$ v(x)=\sqrt{x+2} $$ Write your answer as an inequality. Or, you may instead click on "Empty set" or "All reals" as the answer.

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1. The function is defined as $$ v(x) = \sqrt{x+2} $$.
2. The square root is defined only when the radicand (the expression under the square root) is non-negative. Thus, we require:
   $$
   x+2 \ge 0.
   $$
3. Solve for $$ x $$ by subtracting 2 from both sides:
   $$
   x \ge -2.
   $$

The domain of the function is all real numbers $$ x $$ such that:
$$
x \ge -2.
$$
The domain of the function is all real numbers $$ x $$ where $$ x \ge -2 $$.

Find the domain of the function.

Write your answer as an inequality.
Or, you may instead click on “Empty set” or “All reals” as the answer.

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Find the domain of the function. Write your answer as an inequality. Or, you may instead click on “Empty set” or “All reals” as the answer.