Solve for $$ p \frac{5 p_{3}^{-2}}{3}+\frac{p}{2}=8 $$

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Solve the equation $$ p \frac{5 p_{3}^{-2}}{3}+\frac{p}{2}=8 $$.
Solve the equation by following steps:
- step0: Solve for $$p$$:
  $$p	imes \frac{5p_{3}^{-2}}{3}+\frac{p}{2}=8$$
- step1: Simplify:
  $$\frac{5p}{3p_{3}^{2}}+\frac{p}{2}=8$$
- step2: Multiply both sides of the equation by LCD:
  $$\left(\frac{5p}{3p_{3}^{2}}+\frac{p}{2}ight)	imes 6p_{3}^{2}=8	imes 6p_{3}^{2}$$
- step3: Simplify the equation:
  $$10p+3p_{3}^{2}p=48p_{3}^{2}$$
- step4: Simplify:
  $$\left(10+3p_{3}^{2}ight)p=48p_{3}^{2}$$
- step5: Divide both sides:
  $$\frac{\left(10+3p_{3}^{2}ight)p}{10+3p_{3}^{2}}=\frac{48p_{3}^{2}}{10+3p_{3}^{2}}$$
- step6: Divide the numbers:
  $$p=\frac{48p_{3}^{2}}{10+3p_{3}^{2}}$$
The solution to the equation $$ p \frac{5 p_{3}^{-2}}{3}+\frac{p}{2}=8 $$ is $$ p=\frac{48p_{3}^{2}}{10+3p_{3}^{2}} $$.
$$ p=\frac{48p_{3}^{2}}{10+3p_{3}^{2}} $$

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