Parsons problem Drag the blocks into the dotted area in the correct order. light_color = "green" print("GO") if light_color == "green": print("SLOW") else: elif light_color == "yellow": print("STOP")

To solve the Parsons problem, we need to arrange the blocks of code in the correct order to ensure that the program runs without errors and produces the expected output based on the value of `light_color`. Here’s the correct order of the blocks: 1. `light_color = "green"` 2. `print("GO")` 3. `if light_color == "green":` 4. `print("SLOW")` 5. `elif light_color == "yellow":` 6. `print("STOP")` ### Explanation of the Order: 1. **Set the light color**: The first line initializes the variable `light_color` with the value `"green"`. 2. **Print "GO"**: The second line prints "GO" regardless of the light color. 3. **Check the light color**: The `if` statement checks if `light_color` is `"green"`. 4. **Print "SLOW"**: If the condition is true (which it is, since `light_color` is `"green"`), it prints "SLOW". 5. **Check for yellow**: The `elif` statement checks if `light_color` is `"yellow"`. This will not execute in this case, but it is necessary to include it for proper structure. 6. **Print "STOP"**: This line will not execute in this case since `light_color` is not `"yellow"`. ### Final Code: ```python light_color = "green" print("GO") if light_color == "green": print("SLOW") elif light_color == "yellow": print("STOP") ``` This arrangement ensures that the program runs correctly and produces the expected output based on the value of `light_color`.