horizontal asymptotes of $$ F(x)=\frac{3 x}{x^{2}-4} $$ $$ \begin{array}{ll} ext { Jone } & ext { B. } y=-2,2\end{array} $$

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horizontal asymptotes of $$ F(x)=\frac{3 x}{x^{2}-4} $$ $$ \begin{array}{ll}	ext { Jone } & 	ext { B. } y=-2,2\end{array} $$

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Find the horizontal asymptotes of $$ F(x)=\frac{3x}{x^2-4} $$.
Function by following steps:
- step0: Find the horizontal asymptotes:
  $$F\left(xight)=\frac{3x}{x^{2}-4}$$
- step1: Evaluate the limits $$\lim _{xightarrow +\infty}\left(F\left(xight)ight)$$ and $$\lim _{xightarrow -\infty}\left(F\left(xight)ight):$$
  $$\begin{align}&\lim _{xightarrow +\infty}\left(\frac{3x}{x^{2}-4}ight)\&\lim _{xightarrow -\infty}\left(\frac{3x}{x^{2}-4}ight)\end{align}$$
- step2: Calculate:
  $$\begin{align}&0\&0\end{align}$$
- step3: The finite values are horizontal asymptotes:
  $$\begin{align}&F\left(xight)=0\end{align}$$
The horizontal asymptote of the function $$ F(x)=\frac{3x}{x^2-4} $$ is $$ F(x)=0 $$.
The horizontal asymptote is $$ y=0 $$.

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