AD growth medium is inoculated with 1,000 bacteria, which grow at a rate of \( 15 \% \) each day, What is the population of the oulture 6 days after inoculation? \( y=1,000(1,15)^{6} ; 2,313 \) bacteria \( y=1,000(1.15)^{\%} ; 2,600 \) bacteria \( y=1,000(1.5)^{5} ; 7,594 \) bacteria \( y=1,000(1.5)^{6} ; 11,391 \) bacteria
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In this scenario, the growth of bacteria can be modeled as exponential growth. Starting with 1,000 bacteria and a daily growth rate of 15%, we can safely use the formula \( y = 1,000(1.15)^{6} \). This means the corrected calculation would yield a population of approximately 2,313 bacteria after 6 days of growth. So, the correct response is the first calculation! To visualize this, imagine those 1,000 bacteria as a tiny party. Each day, they invite 15% more friends! By day six, that party has grown significantly, showing how exponential growth can lead to big numbers in a surprisingly short time!