Solve equation by completing the square. List the s $$ 2 m^{2}+3 m-4=0 $$

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Solve the equation $$ 2m^{2}+3m-4=0 $$.
Solve the quadratic equation by following steps:
- step0: Solve using the quadratic formula:
  $$2m^{2}+3m-4=0$$
- step1: Solve using the quadratic formula:
  $$m=\frac{-3\pm \sqrt{3^{2}-4\times 2\left(-4\right)}}{2\times 2}$$
- step2: Simplify the expression:
  $$m=\frac{-3\pm \sqrt{3^{2}-4\times 2\left(-4\right)}}{4}$$
- step3: Simplify the expression:
  $$m=\frac{-3\pm \sqrt{41}}{4}$$
- step4: Separate into possible cases:
  $$\begin{align}&m=\frac{-3+\sqrt{41}}{4}\&m=\frac{-3-\sqrt{41}}{4}\end{align}$$
- step5: Rewrite the fraction:
  $$\begin{align}&m=\frac{-3+\sqrt{41}}{4}\&m=-\frac{3+\sqrt{41}}{4}\end{align}$$
- step6: Rewrite:
  $$m_{1}=-\frac{3+\sqrt{41}}{4},m_{2}=\frac{-3+\sqrt{41}}{4}$$
The solutions to the equation $$2m^{2}+3m-4=0$$ by completing the square are:

$$ m_{1}=-\frac{3+\sqrt{41}}{4} $$
$$ m_{2}=-\frac{3-\sqrt{41}}{4} $$
$$ m_{1}=-\frac{3+\sqrt{41}}{4}, m_{2}=-\frac{3-\sqrt{41}}{4} $$

Solve equation by completing the square. List the s

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