3. Use column method to solve: $$ \mathrm{R} 20,89+\mathrm{R} 31,99 $$. $$ \begin{array}{r} \text { ro, 89 } \ +31,99 \ \hline 1232,88 \end{array} $$ 4. Use column method to solve: $$ 4 \times 0,287 $$ $$ \qquad $$ $$ \begin{array}{r} \frac{1,3}{6,87} \ x \quad 1 \ \hline 1,148 \end{array} $$ 4.5. Solve $$ 5,897 \div 2 $$. 48 2 , aus srewn $$ 2) 5,897 $$

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To solve the given problems using the column method, we will perform the calculations step by step.

### Problem 1: $$ \mathrm{R} 20,89+\mathrm{R} 31,99 $$

Given:
$$ \mathrm{R} 20,89+\mathrm{R} 31,99 $$

Using the column method:
$$ \begin{array}{r} \text { ro, 89 } \ +31,99 \ \hline 1232,88 \end{array} $$

The result of $$ \mathrm{R} 20,89+\mathrm{R} 31,99 $$ is $$ \mathrm{R} 1232,88 $$.

### Problem 2: $$ 4 \times 0,287 $$

Given:
$$ 4 \times 0,287 $$

Using the column method:
$$ \begin{array}{r} \frac{1,3}{6,87} \ x \quad 1 \ \hline 1,148 \end{array} $$

The result of $$ 4 \times 0,287 $$ is $$ 1,148 $$.

### Problem 3: $$ 5,897 \div 2 $$

Given:
$$ 5,897 \div 2 $$

Using the column method:
$$ \begin{array}{r} \text { ro, 89 } \ +31,99 \ \hline 1232,88 \end{array} $$

The result of $$ 5,897 \div 2 $$ is $$ 2,948,5 $$.
- $$ \mathrm{R} 20,89 + \mathrm{R} 31,99 = \mathrm{R} 1232,88 $$ - $$ 4 \times 0,287 = 1,148 $$ - $$ 5,897 \div 2 = 2,948.5 $$

Use column method to solve: .

Use column method to solve:

4.5. Solve . 48
2 , aus srewn

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Use column method to solve: . Use column method to solve: 4.5. Solve . 48 2 , aus srewn