Pregunta
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Evaluate each expression. 1) \( (-17-3-5) \div(-4-1) \) 2) \( (15-5) \div-2 \cdot 2 \cdot-6 \) 3) \( -4 \div(4-(2 \cdot 6-4)) \) 4) \( -6+1--3+-6-1 \) 5) \( -3-4+4-(-1--1) \) 6) \( -\frac{4}{4(3-4)}(-5-6) \) 7) \( \frac{-8-1-2+2}{-5--2} \) 8) \( \frac{-2-1+-10+5}{1+1} \) 9) \( -5 \cdot 2+4-2+-1+2 \) 10) \( (5-1-1) \cdot(-5+3) \cdot-6 \) 11) \( (5-4)(6)-(5-(6-6)) \) 12) \( 4+\frac{9-6}{1+4-2} \) 13) \( \left(3^{2}\right)\left(\frac{8}{2-(2-2)}\right) \) 14) \( 3^{3}-\frac{9}{(3)(4-3)} \) 15) \( \left(\frac{5}{(2)(5)-5}\right)(6)-4 \)

Ask by Alexander Goodwin. in the United States
Jan 23,2025

Solución de tutoría real

Respuesta verificada por el tutor

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1. **5** 2. **60** 3. **1** 4. **-9** 5. **-3** 6. **-11** 7. **3** 8. **-4** 9. **-7** 10. **36** 11. **1** 12. **5** 13. **36** 14. **24** 15. **2**

Solución

Sure, let's evaluate each expression step by step: --- ### **1) \( (-17 - 3 - 5) \div (-4 - 1) \)** **Step 1:** Calculate the numerator: \[ -17 - 3 - 5 = -25 \] **Step 2:** Calculate the denominator: \[ -4 - 1 = -5 \] **Step 3:** Divide the numerator by the denominator: \[ \frac{-25}{-5} = 5 \] **Answer:** **5** --- ### **2) \( (15 - 5) \div -2 \cdot 2 \cdot -6 \)** **Step 1:** Calculate inside the parentheses: \[ 15 - 5 = 10 \] **Step 2:** Perform the division: \[ \frac{10}{-2} = -5 \] **Step 3:** Multiply by 2: \[ -5 \cdot 2 = -10 \] **Step 4:** Multiply by -6: \[ -10 \cdot -6 = 60 \] **Answer:** **60** --- ### **3) \( -4 \div (4 - (2 \cdot 6 - 4)) \)** **Step 1:** Calculate inside the innermost parentheses: \[ 2 \cdot 6 = 12 \] \[ 12 - 4 = 8 \] **Step 2:** Subtract from 4: \[ 4 - 8 = -4 \] **Step 3:** Divide -4 by -4: \[ \frac{-4}{-4} = 1 \] **Answer:** **1** --- ### **4) \( -6 + 1 --3 + -6 -1 \)** **Step 1:** Simplify the double negative: \[ --3 = +3 \] **Step 2:** Combine all terms: \[ -6 + 1 + 3 - 6 - 1 = -9 \] **Answer:** **-9** --- ### **5) \( -3 -4 +4 -(-1 --1) \)** **Step 1:** Simplify the double negative: \[ -(-1 --1) = -(-1 + 1) = -0 = 0 \] **Step 2:** Combine all terms: \[ -3 - 4 + 4 + 0 = -3 \] **Answer:** **-3** --- ### **6) \( -\frac{4}{4(3 -4)}(-5 -6) \)** **Step 1:** Calculate the denominator inside the fraction: \[ 4(3 - 4) = 4 \times (-1) = -4 \] **Step 2:** Divide -4 by -4: \[ \frac{-4}{-4} = 1 \] **Step 3:** Multiply by (-5 -6): \[ 1 \times (-11) = -11 \] **Answer:** **-11** --- ### **7) \( \frac{-8 -1 -2 +2}{-5 --2} \)** **Step 1:** Simplify the denominator: \[ -5 --2 = -5 + 2 = -3 \] **Step 2:** Combine the numerator: \[ -8 - 1 - 2 + 2 = -9 \] **Step 3:** Divide: \[ \frac{-9}{-3} = 3 \] **Answer:** **3** --- ### **8) \( \frac{-2 -1 + -10 +5}{1 +1} \)** **Step 1:** Combine the numerator: \[ -2 - 1 - 10 + 5 = -8 \] **Step 2:** Add the denominator: \[ 1 + 1 = 2 \] **Step 3:** Divide: \[ \frac{-8}{2} = -4 \] **Answer:** **-4** --- ### **9) \( -5 \cdot 2 +4 -2 + -1 +2 \)** **Step 1:** Multiply: \[ -5 \cdot 2 = -10 \] **Step 2:** Combine all terms: \[ -10 + 4 - 2 - 1 + 2 = -7 \] **Answer:** **-7** --- ### **10) \( (5 -1 -1) \cdot (-5 +3) \cdot -6 \)** **Step 1:** Calculate inside the first parentheses: \[ 5 - 1 - 1 = 3 \] **Step 2:** Calculate inside the second parentheses: \[ -5 + 3 = -2 \] **Step 3:** Multiply all terms: \[ 3 \cdot (-2) \cdot -6 = 36 \] **Answer:** **36** --- ### **11) \( (5-4)(6) - (5 - (6-6)) \)** **Step 1:** Simplify the first part: \[ 5 - 4 = 1 \] \[ 1 \cdot 6 = 6 \] **Step 2:** Simplify inside the second parentheses: \[ 6 - 6 = 0 \] \[ 5 - 0 = 5 \] **Step 3:** Subtract: \[ 6 - 5 = 1 \] **Answer:** **1** --- ### **12) \( 4 + \frac{9 - 6}{1 + 4 - 2} \)** **Step 1:** Calculate the numerator inside the fraction: \[ 9 - 6 = 3 \] **Step 2:** Calculate the denominator inside the fraction: \[ 1 + 4 - 2 = 3 \] **Step 3:** Divide: \[ \frac{3}{3} = 1 \] **Step 4:** Add: \[ 4 + 1 = 5 \] **Answer:** **5** --- ### **13) \( \left(3^{2}\right) \left(\frac{8}{2 - (2-2)}\right) \)** **Step 1:** Calculate the exponent: \[ 3^2 = 9 \] **Step 2:** Simplify inside the fraction: \[ 2 - (2 - 2) = 2 - 0 = 2 \] **Step 3:** Divide: \[ \frac{8}{2} = 4 \] **Step 4:** Multiply: \[ 9 \times 4 = 36 \] **Answer:** **36** --- ### **14) \( 3^{3} - \frac{9}{(3)(4-3)} \)** **Step 1:** Calculate the exponent: \[ 3^3 = 27 \] **Step 2:** Simplify inside the denominator: \[ 3 \times (4 - 3) = 3 \times 1 = 3 \] **Step 3:** Divide: \[ \frac{9}{3} = 3 \] **Step 4:** Subtract: \[ 27 - 3 = 24 \] **Answer:** **24** --- ### **15) \( \left(\frac{5}{(2)(5) -5}\right)(6) -4 \)** **Step 1:** Calculate the denominator inside the fraction: \[ (2)(5) - 5 = 10 - 5 = 5 \] **Step 2:** Divide: \[ \frac{5}{5} = 1 \] **Step 3:** Multiply: \[ 1 \times 6 = 6 \] **Step 4:** Subtract: \[ 6 - 4 = 2 \] **Answer:** **2** --- ### **Summary of Answers** 1. **5** 2. **60** 3. **1** 4. **-9** 5. **-3** 6. **-11** 7. **3** 8. **-4** 9. **-7** 10. **36** 11. **1** 12. **5** 13. **36** 14. **24** 15. **2**

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Let's tackle these expressions one by one: 1) \( (-17-3-5) \div(-4-1) = (-25) \div (-5) = 5 \) 2) \( (15-5) \div -2 \cdot 2 \cdot -6 = 10 \div -2 \cdot 2 \cdot -6 = -5 \cdot 2 \cdot -6 = 60 \) 3) \( -4 \div (4 - (2 \cdot 6 - 4)) = -4 \div (4 - (12 - 4)) = -4 \div (-4) = 1 \) 4) \( -6 + 1 - -3 + -6 - 1 = -6 + 1 + 3 - 6 - 1 = -9 \) 5) \( -3 - 4 + 4 - (-1 - -1) = -3 - 4 + 4 - (0) = -3 \) 6) \( -\frac{4}{4(3-4)}(-5-6) = -\frac{4}{4(-1)}(-11) = -\frac{4}{-4}(-11) = 11 \) 7) \( \frac{-8-1-2+2}{-5--2} = \frac{-9}{-3} = 3 \) 8) \( \frac{-2-1+-10+5}{1+1} = \frac{-8}{2} = -4 \) 9) \( -5 \cdot 2 + 4 - 2 + -1 + 2 = -10 + 4 - 2 - 1 + 2 = -7 \) 10) \( (5-1-1) \cdot(-5+3) \cdot -6 = (3) \cdot(-2) \cdot -6 = 36 \) 11) \( (5-4)(6)-(5-(6-6)) = (1)(6) - (5-0) = 6 - 5 = 1 \) 12) \( 4 + \frac{9-6}{1+4-2} = 4 + \frac{3}{3} = 4 + 1 = 5 \) 13) \( \left(3^{2}\right)\left(\frac{8}{2-(2-2)}\right) = 9 \cdot \text{undefined} = \text{undefined} \) (division by zero) 14) \( 3^{3}-\frac{9}{(3)(4-3)} = 27 - \frac{9}{3} = 27 - 3 = 24 \) 15) \( \left(\frac{5}{(2)(5)-5}\right)(6)-4 = \left(\frac{5}{5}\right)(6)-4 = 6 - 4 = 2 \) So, after evaluating each expression, we have the results as follows: 1) 5 2) 60 3) 1 4) -9 5) -3 6) 11 7) 3 8) -4 9) -7 10) 36 11) 1 12) 5 13) undefined 14) 24 15) 2

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