Question 3
Calculate the probability for the following problems (Please keep 4 decimal places).

Ask by Kirk Pearson. in the United States

Mar 14,2025

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Question 3 Calculate the probability for the following problems (Please keep 4 decimal places). 1. $$ P(\mathrm{Z}>2.19)= $$ 3. $$ P(-2.35<2.1)= $$

UpStudy AI · Accepted Answer

It appears that I am unable to directly calculate the probabilities using the tools available. Instead, I will provide the calculations manually using standard normal distribution tables or a calculator. ### Step 1: Calculate $$ P(Z > 2.19) $$ 1. **Find $$ P(Z \leq 2.19) $$**: - Using a standard normal distribution table or calculator, we find: $$ P(Z \leq 2.19) \approx 0.9857 $$ 2. **Calculate $$ P(Z > 2.19) $$**: $$ P(Z > 2.19) = 1 - P(Z \leq 2.19) = 1 - 0.9857 = 0.0143 $$ ### Step 2: Calculate $$ P(-2.35 < Z < 2.1) $$ 1. **Find $$ P(Z < 2.1) $$**: - Using a standard normal distribution table or calculator, we find: $$ P(Z < 2.1) \approx 0.9821 $$ 2. **Find $$ P(Z \leq -2.35) $$**: - Using a standard normal distribution table or calculator, we find: $$ P(Z \leq -2.35) \approx 0.0094 $$ 3. **Calculate $$ P(-2.35 < Z < 2.1) $$**: $$ P(-2.35 < Z < 2.1) = P(Z < 2.1) - P(Z \leq -2.35) = 0.9821 - 0.0094 = 0.9727 $$ ### Final Answers 1. $$ P(Z > 2.19) \approx 0.0143 $$ 2. $$ P(-2.35 < Z < 2.1) \approx 0.9727 $$ Thus, the probabilities are: - $$ P(Z > 2.19) = 0.0143 $$ - $$ P(-2.35 < Z < 2.1) = 0.9727 $$ $$ P(Z > 2.19) = 0.0143 $$ $$ P(-2.35 < Z < 2.1) = 0.9727 $$

Question 3
Calculate the probability for the following problems (Please keep 4 decimal places).

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