c. For those that graph as lines, determine the slope and vertical intercept. $$ y=\frac{1}{x} $$ $$ y=\sqrt{x} \quad y=x \quad y=\frac{x+15}{2} $$

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1. $$ y=\frac{1}{x} $$ and $$ y=\sqrt{x} $$ are not linear functions.

2. For $$ y=x $$:  
  - The function is of the form $$ y=1\cdot x+0 $$.  
  - **Slope:** $$ 1 $$  
  - **Vertical intercept:** $$ 0 $$

3. For $$ y=\frac{x+15}{2} $$:  
  - Rewrite the equation in slope-intercept form:  
    $$
    y=\frac{1}{2}x+\frac{15}{2}
    $$  
  - **Slope:** $$ \frac{1}{2} $$  
  - **Vertical intercept:** $$ \frac{15}{2} $$
For the linear functions: - $$ y = x $$: Slope = 1, Vertical Intercept = 0 - $$ y = \frac{x + 15}{2} $$: Slope = 0.5, Vertical Intercept = 7.5

c. For those that graph as lines, determine the slope and vertical intercept.

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