\begin{tabular}{|l|l|}\hline Listen \\ The Brittle Bird Store prepares bird-seed blends by mixing sunflower seeds and millet and packaging them in 5 -pound bags for \\ sale. Sunflower seed \( (s) \) is regularly sold for \( \$ 1.75 \) per pound, and millet \( (m) \) is sold for \( \$ 2.50 \) per pound. The mixture is sold \\ for \( \$ 11.60 \). \\ How many pounds of sunflower seed does the mixture contain? \end{tabular} .

To solve this problem, we'll set up a system of equations based on the information provided. Let \( s \) be the pounds of sunflower seeds and \( m \) be the pounds of millet in the mixture. We know the total weight of the mixture is 5 pounds, so we can create the first equation: \[ s + m = 5 \] Next, we know the cost of the blends. The total cost of the mixture is given as $11.60, and we can express this with our second equation based on the costs of each seed: \[ 1.75s + 2.50m = 11.60 \] Now, we can solve these equations simultaneously. From the first equation, we can express \( m \): \[ m = 5 - s \] Now we can substitute this expression for \( m \) in the second equation: \[ 1.75s + 2.50(5 - s) = 11.60 \] Distributing the 2.50 gives us: \[ 1.75s + 12.50 - 2.50s = 11.60 \] Combining like terms: \[ -0.75s + 12.50 = 11.60 \] Now we can isolate \( s \): \[ -0.75s = 11.60 - 12.50 \] \[ -0.75s = -0.90 \] \[ s = \frac{-0.90}{-0.75} \] \[ s = 1.2 \] So, the mixture contains **1.2 pounds of sunflower seed**. Now substituting \( s = 1.2 \) back into the equation for \( m \): \[ m = 5 - 1.2 \] \[ m = 3.8 \] So, there are **3.8 pounds of millet** in the mixture as well!