V) \( [248 \div 2+3 \times 17-(128 \div 2+3 \times 15)]= \)

To solve the expression \( [248 \div 2 + 3 \times 17 - (128 \div 2 + 3 \times 15)] \), we evaluate it step by step: 1. **Calculate \( 248 \div 2 \):** \( 248 \div 2 = 124 \) 2. **Calculate \( 3 \times 17 \):** \( 3 \times 17 = 51 \) 3. **Combine these results:** \( 124 + 51 = 175 \) 4. **Now solve the expression within the parentheses: \( (128 \div 2 + 3 \times 15) \)** 5. **Calculate \( 128 \div 2 \):** \( 128 \div 2 = 64 \) 6. **Calculate \( 3 \times 15 \):** \( 3 \times 15 = 45 \) 7. **Combine these results:** \( 64 + 45 = 109 \) 8. **Finally, substitute back into the main expression:** \( 175 - 109 = 66 \) So, the final result is: \[ 66 \]