Find the $$ x $$-intercept and $$ y $$-intercept of the line. $$ \begin{array}{l}5 x-7 y=35 \ x \text {-intercept: } \square \ y \text {-intercept: }\end{array} $$

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To find the $$ x $$-intercept and $$ y $$-intercept of the line given by the equation $$ 5x - 7y = 35 $$, we can follow these steps:

### Step 1: Find the $$ x $$-intercept
The $$ x $$-intercept occurs when $$ y = 0 $$. We can substitute $$ y = 0 $$ into the equation and solve for $$ x $$.

$$
5x - 7(0) = 35
$$

This simplifies to:

$$
5x = 35
$$

Now, divide both sides by 5:

$$
x = \frac{35}{5} = 7
$$

Thus, the $$ x $$-intercept is $$ (7, 0) $$.

### Step 2: Find the $$ y $$-intercept
The $$ y $$-intercept occurs when $$ x = 0 $$. We can substitute $$ x = 0 $$ into the equation and solve for $$ y $$.

$$
5(0) - 7y = 35
$$

This simplifies to:

$$
-7y = 35
$$

Now, divide both sides by -7:

$$
y = \frac{35}{-7} = -5
$$

Thus, the $$ y $$-intercept is $$ (0, -5) $$.

### Summary of Results
- $$ x $$-intercept: $$ (7, 0) $$
- $$ y $$-intercept: $$ (0, -5) $$
The $$ x $$-intercept is $$ (7, 0) $$ and the $$ y $$-intercept is $$ (0, -5) $$.

Find the \( x \)-intercept and \( y \)-intercept of the line. \[ \begin{array}{l}5 x-7 y=35 \\ x \text {-intercept: } \square \\ y \text {-intercept: }\end{array} \]

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