In the following exercise, you will be given the opportunity to recall what happens when you add two linear functions. Given: \( f(x)=2 x+3, g(x)=x+2 \), \( h(x)=x-5, m(x)=-3 x-1 \) 2. \( q(x)=g(x)+h(x) \) a. Write the equation of \( q(x) \). b. In what way is the slope of \( q(x) \) related to the slope of \( g(x) \) and the slope of \( h(x) \) ? (Include increasing or decreasing in your answer. Also identify which function is increasing faster.) c. In what way is the \( y \)-intercept of \( q(x) \) related to the \( y \)-intercepts of \( g(x) \) and of \( h(x) \) ? d. Is \( q(x) \) the equation of a line? Justify your answer.
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To find the equation of \( q(x) \), simply add the two linear functions together. So, \( q(x) = g(x) + h(x) = (x + 2) + (x - 5) = 2x - 3 \). Regarding the slope, \( g(x) \) has a slope of 1 (increasing), while \( h(x) \) has a slope of 1 (increasing). Therefore, the slope of \( q(x) \) is the sum of the slopes of both functions: 1 + 1 = 2, which means \( q(x) \) is increasing faster than either \( g(x) \) or \( h(x) \). The \( y \)-intercept of \( q(x) \) can be found directly from the equation \( q(x) = 2x - 3 \), which is -3. The \( y \)-intercepts of \( g(x) \) and \( h(x) \) are 2 and -5, respectively. For \( q(x) \), the \( y \)-intercept is the sum of the \( y \)-intercepts of \( g(x) \) and \( h(x) \): 2 + (-5) = -3. Yes, \( q(x) \) is the equation of a line. It represents a linear function because its equation is in the form \( y = mx + b \), where \( m \) is the slope (2) and \( b \) is the \( y \)-intercept (-3). Linear functions are always graphed as straight lines, so you can count on \( q(x) \) being one too!