Solve for x in the quadratic equation: $$ 2x^{2} + 4x - 6 = 0 $$

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Solve the equation $$ 2x^{2} + 4x - 6 = 0 $$.
Solve the quadratic equation by following steps:
- step0: Solve by factoring:
  $$2x^{2}+4x-6=0$$
- step1: Factor the expression:
  $$2\left(x-1ight)\left(x+3ight)=0$$
- step2: Divide the terms:
  $$\left(x-1ight)\left(x+3ight)=0$$
- step3: Separate into possible cases:
  $$\begin{align}&x-1=0\&x+3=0\end{align}$$
- step4: Solve the equation:
  $$\begin{align}&x=1\&x=-3\end{align}$$
- step5: Rewrite:
  $$x_{1}=-3,x_{2}=1$$
The solutions to the quadratic equation $$2x^{2} + 4x - 6 = 0$$ are $$x = -3$$ and $$x = 1$$.
The solutions are $$x = -3$$ and $$x = 1$$.

Solve for x in the quadratic equation:

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