Solve for $$ x $$ $$ (x+2)(x-3) $$

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The provided equation is not in the correct format for solving. Let's rewrite the equation as $$ (x+2)(x-3) = 0 $$ and then solve for $$ x $$.
Solve the quadratic equation by following steps:
- step0: Solve by factoring:
  $$\left(x+2ight)\left(x-3ight)=0$$
- step1: Separate into possible cases:
  $$\begin{align}&x-3=0\&x+2=0\end{align}$$
- step2: Solve the equation:
  $$\begin{align}&x=3\&x=-2\end{align}$$
- step3: Rewrite:
  $$x_{1}=-2,x_{2}=3$$
The solutions to the equation $$ (x+2)(x-3) = 0 $$ are $$ x = -2 $$ and $$ x = 3 $$.
The solutions are $$ x = -2 $$ and $$ x = 3 $$.

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