12. $$ \frac{50}{6}+\frac{3}{7}

Question

12. $$ \frac{50}{6}+\frac{3}{7}<\frac{5}{6} $$

UpStudy AI · Accepted Answer

Let's evaluate the inequality: $$ \frac{50}{6} + \frac{3}{7} < \frac{5}{6} $$ ### Step 1: Simplify the Left Side First, calculate each fraction separately: 1. **$$\frac{50}{6}$$**: $$ \frac{50}{6} = 8.\overline{3} \quad \text{(approximately } 8.3333\text{)} $$ 2. **$$\frac{3}{7}$$**: $$ \frac{3}{7} \approx 0.4286 $$ Now, add them together: $$ \frac{50}{6} + \frac{3}{7} \approx 8.3333 + 0.4286 = 8.7619 $$ ### Step 2: Simplify the Right Side $$ \frac{5}{6} \approx 0.8333 $$ ### Step 3: Compare Both Sides Now, compare the two results: $$ 8.7619 \quad \text{(Left Side)} \quad \text{vs.} \quad 0.8333 \quad \text{(Right Side)} $$ Clearly, $$ 8.7619 > 0.8333 $$ ### Conclusion The original inequality states that: $$ \frac{50}{6} + \frac{3}{7} < \frac{5}{6} $$ However, as we've calculated: $$ 8.7619 > 0.8333 $$ **Therefore, the inequality is FALSE.** The inequality $$\frac{50}{6} + \frac{3}{7} < \frac{5}{6}$$ is **false** because $$\frac{50}{6} + \frac{3}{7} \approx 8.7619$$ is greater than $$\frac{5}{6} \approx 0.8333$$.

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Solución

Step 1: Simplify the Left Side

Step 2: Simplify the Right Side

Step 3: Compare Both Sides

Conclusion

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