The value \( V \) (in dollars) of a vehicle depends on the miles \( x \) that it has been driven. This is given in the formula \( V=22,000-0.25 x \). After one year, the value of a vehicle is between \( \$ 12,000 \) and \( \$ 15,000 \). Which range of miles driven corresponds to this range of values based on the given formula?
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To find the range of miles driven that corresponds to a vehicle value between \$12,000 and \$15,000 using the formula \( V = 22,000 - 0.25x \), we can set up two inequalities. For \( V = 12,000 \): \[ 12,000 = 22,000 - 0.25x \] \[ 0.25x = 22,000 - 12,000 \] \[ 0.25x = 10,000 \] \[ x = \frac{10,000}{0.25} = 40,000 \] For \( V = 15,000 \): \[ 15,000 = 22,000 - 0.25x \] \[ 0.25x = 22,000 - 15,000 \] \[ 0.25x = 7,000 \] \[ x = \frac{7,000}{0.25} = 28,000 \] Thus, the range of miles driven that corresponds to a vehicle value between \$12,000 and \$15,000 is between 28,000 miles and 40,000 miles. Therefore, the answer is \( 28,000 \leq x \leq 40,000 \).