$$ -12 \mathrm{~cm} $$ $$ \qquad $$ 4 9 cm You want to catch rainwater in this cylindrical container: About how much water will it hold?

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To determine how much rainwater the cylindrical container can hold, we'll calculate its volume using the formula for the volume of a cylinder:

$$
\text{Volume} = \pi r^2 h
$$

Where:
- $$ r $$ is the radius of the cylinder.
- $$ h $$ is the height of the cylinder.
- $$ \pi $$ (pi) is approximately 3.14159.

From the information provided:
- It seems the cylinder has a **radius ($$ r $$) of 4 cm**.
- The **height ($$ h $$) is 9 cm**.

Using these values:

$$
\text{Volume} = \pi \times (4\, \text{cm})^2 \times 9\, \text{cm}
$$
$$
\text{Volume} = \pi \times 16\, \text{cm}^2 \times 9\, \text{cm}
$$
$$
\text{Volume} = 144\pi\, \text{cm}^3
$$
$$
\text{Volume} \approx 144 \times 3.14159\, \text{cm}^3
$$
$$
\text{Volume} \approx 452.39\, \text{cm}^3
$$

**Conclusion:**
The cylindrical container can hold approximately **452 cubic centimeters (cm³)** of water. Since 1 liter is equivalent to 1,000 cm³, this is also about **0.452 liters** of water.
The cylindrical container can hold approximately 452 cubic centimeters (cm³) of water.

\( -12 \mathrm{~cm} \) \( \qquad \) 4 9 cm You want to catch rainwater in this cylindrical container: About how much water will it hold?

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