11. (i) Solve the inequality \( \frac{4(16-3 y)}{5} \leqslant 2 \frac{1}{5} \). (ii) Find the least possible value of \( y \) such that \( y \) is a perfect square.

To solve the inequality \( \frac{4(16-3y)}{5} \leqslant 2 \frac{1}{5} \), first convert \( 2 \frac{1}{5} \) to an improper fraction: \( 2 \frac{1}{5} = \frac{11}{5} \). Now, multiply both sides of the inequality by 5 to eliminate the denominator: \[ 4(16 - 3y) \leqslant 11. \] Next, divide both sides by 4: \[ 16 - 3y \leqslant \frac{11}{4}. \] Subtract 16 from both sides: \[ -3y \leqslant \frac{11}{4} - 16 = \frac{11 - 64}{4} = \frac{-53}{4}. \] Now, divide by -3 (remember to reverse the inequality): \[ y \geqslant \frac{53}{12}. \] To find the least possible value of \( y \) such that \( y \) is a perfect square, the smallest perfect square greater than or equal to \( \frac{53}{12} \approx 4.4167 \) is \( 9 \), since \( 3^2 = 9 \). Therefore, the least possible value of \( y \) is \( 9 \).