What is the solution to the system of equations? \( \left\{\begin{array}{l}6 x-4 y=12 \\ -3 x+2 y=-6\end{array}\right. \)

Solve the system of equations \( 6x-4y=12;-3x+2y=-6 \). Solve the system of equations by following steps: - step0: Solve using the substitution method: \(\left\{ \begin{array}{l}6x-4y=12\\-3x+2y=-6\end{array}\right.\) - step1: Rearrange the terms: \(6x-4y=12\) - step2: Move the expression to the right side: \(6x=12+4y\) - step3: Divide both sides: \(\frac{6x}{6}=\frac{12+4y}{6}\) - step4: Divide the numbers: \(x=\frac{6+2y}{3}\) - step5: Calculate: \(\left(x,y\right) = \left(\frac{6+2y}{3},y\right),y \in \mathbb{R}\) - step6: Alternative Form: \(\textrm{Infinitely many solutions}\) The system of equations \( \left\{\begin{array}{l}6 x-4 y=12 \\ -3 x+2 y=-6\end{array}\right. \) has infinitely many solutions.