Suppose that the function $$ g $$ is defined, for all real numbers, as follows. \[ g(x)=\left\{\begin{array}{ll}2 & \text { if } x \leq-2 \ -(x-1)^{2}+2 & \text { if }-2

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1. To compute $$ g(-5) $$, note that since $$-5 \leq -2$$, we use the first piece of the definition:
   $$
   g(x) = 2 \quad \text{for } x \leq -2.
   $$
   Therefore, 
   $$
   g(-5) = 2.
   $$

2. To compute $$ g(-2) $$, observe that $$-2$$ satisfies the condition $$ x \leq -2 $$, so again:
   $$
   g(x) = 2 \quad \text{for } x \leq -2.
   $$
   Hence,
   $$
   g(-2) = 2.
   $$
$$ g(-5) = 2 $$ and $$ g(-2) = 2 $$.

Suppose that the function is defined, for all real numbers, as follows.

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