\( 1 \leftarrow \quad \) Solve. Check your solution. \( 2=z+15 \) \( z=\square \)

To solve the equation \( 2 = z + 15 \), you need to isolate \( z \). Start by subtracting 15 from both sides of the equation: \( 2 - 15 = z \) This simplifies to: \( -13 = z \) Thus, the solution is \( z = -13 \). To check your solution, substitute \( z \) back into the original equation: \( 2 = -13 + 15 \) Calculating the right side gives: \( 2 = 2 \) Since both sides of the equation are equal, your solution \( z = -13 \) is correct!