\begin{tabular}{l}9 Numeric 1 point \ Evaluate when $$ Y=5 $$ \ $$ Y^{2}+2 Y+3 $$ \ Type your answer... \ $$ \begin{array}{l} ext { Evaluate when } A=7 \ 5 A+2^{2}(3+5)\end{array} $$ \ $$ \begin{array}{l} ext { Numer }\end{array} $$ \ \hline\end{tabular}

Question

\begin{tabular}{l}9 Numeric 1 point \ Evaluate when $$ Y=5 $$ \ $$ Y^{2}+2 Y+3 $$ \ Type your answer... \ $$ \begin{array}{l}	ext { Evaluate when } A=7 \ 5 A+2^{2}(3+5)\end{array} $$ \ $$ \begin{array}{l}	ext { Numer }\end{array} $$ \ \hline\end{tabular}

UpStudy AI · Accepted Answer

Let's evaluate the expressions step by step.

### Step 1: Evaluate $$ Y^2 + 2Y + 3 $$ when $$ Y = 5 $$

Substituting $$ Y = 5 $$ into the expression:

$$
Y^2 + 2Y + 3 = 5^2 + 2(5) + 3
$$

Calculating each term:

- $$ 5^2 = 25 $$
- $$ 2(5) = 10 $$

Now, adding these values together:

$$
25 + 10 + 3 = 38
$$

So, the value of $$ Y^2 + 2Y + 3 $$ when $$ Y = 5 $$ is **38**.

### Step 2: Evaluate $$ 5A + 2^2(3 + 5) $$ when $$ A = 7 $$

Substituting $$ A = 7 $$ into the expression:

$$
5A + 2^2(3 + 5) = 5(7) + 2^2(3 + 5)
$$

Calculating each term:

- $$ 5(7) = 35 $$
- $$ 2^2 = 4 $$
- $$ 3 + 5 = 8 $$

Now, substituting these values back into the expression:

$$
5(7) + 4(8) = 35 + 32
$$

Adding these values together:

$$
35 + 32 = 67
$$

So, the value of $$ 5A + 2^2(3 + 5) $$ when $$ A = 7 $$ is **67**.

### Final Answers

- The value of $$ Y^2 + 2Y + 3 $$ when $$ Y = 5 $$ is **38**.
- The value of $$ 5A + 2^2(3 + 5) $$ when $$ A = 7 $$ is **67**.
When $$ Y = 5 $$, $$ Y^2 + 2Y + 3 = 38 $$. When $$ A = 7 $$, $$ 5A + 2^2(3 + 5) = 67 $$.

\begin{tabular}{l}9 Numeric 1 point \\ Evaluate when \( Y=5 \) \\ \( Y^{2}+2 Y+3 \) \\ Type your answer... \\ \( \begin{array}{l}\text { Evaluate when } A=7 \\ 5 A+2^{2}(3+5)\end{array} \) \\ \( \begin{array}{l}\text { Numer }\end{array} \) \\ \hline\end{tabular}

Solución de tutoría real

Responder

Solución

Mind Expander

preguntas relacionadas

Latest Algebra Questions