A roulette wheel has 40 slots around the rim, 38 slots are numbered from 11 to 38 . Half of these 38 slots are red, and the other half are black. The remaining 2 slots are numbered 0 and 00 and are green. As the rouleme wheel is spun in one direction, a small ivory ball is rolled along the rim in opposite direction. The ball has an equality likely chance of falling into any one of the 40 slots. Find the probabilities of the events listed in parts ( through (d) below. c. Ball does not land on a number from 25 through 29 The probability of the event that the ball does not land of a number from 25 through 29 is \( \frac{7}{8} \) (Type an integer or a simplified fraction.) d. Ball lands on an even number or on a green slot The probability of the event that the ball lands on an even number or on a green slot is \( \square \). (Type an integer or a simplified fraction.)

To find the probability that the ball lands on an even number or on a green slot, let's first break down the total number of outcomes and favorable outcomes. There are 40 slots in total. Out of the 38 numbered slots (11 to 38), the even numbers are: 12, 14, 16, 18, 20, 22, 24, 26, 28, 30, 32, 34, 36, and 38, making a total of 14 even numbers. Additionally, there are 2 green slots (0 and 00). To find the total number of favorable outcomes, we need to add the even numbers (14) to the green slots (2) but ensure that we don't count them twice. Since none of the green slots are even, we simply add them together: Number of favorable outcomes = Even numbers + Green slots = 14 + 2 = 16. Now, the probability is calculated as the number of favorable outcomes divided by the total number of outcomes: \[ P(\text{even or green}) = \frac{16}{40} = \frac{2}{5}. \] Therefore, the probability that the ball lands on an even number or on a green slot is \( \frac{2}{5} \).