Khloe invested $$ \$ 11,000 $$ in an account paying an interest rate of $$ 4.8 \% $$ compounded continuously. Assuming no deposits or withdrawals are made, how much money, to the nearest ten dollars, would be in the account after 17 years?

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To find the amount of money in the account after 17 years, we can use the formula for continuous compounding:

$$ A = P \times e^{r \times t} $$

Where:
- $$ A $$ is the amount of money in the account after $$ t $$ years,
- $$ P $$ is the principal amount (initial investment),
- $$ r $$ is the interest rate (in decimal form),
- $$ t $$ is the time in years.

Given:
- $$ P = \$11,000 $$
- $$ r = 4.8\% = 0.048 $$ (in decimal form)
- $$ t = 17 $$ years

Substitute the values into the formula:

$$ A = 11000 \times e^{0.048 \times 17} $$

Now, we can calculate the amount of money in the account after 17 years.
Calculate the value by following steps:
- step0: Calculate:
  $$11000e^{0.048\times 17}$$
- step1: Multiply the numbers:
  $$11000e^{0.816}$$
- step2: Convert the expressions:
  $$11000e^{\frac{102}{125}}$$
- step3: Rewrite the expression:
  $$11000\sqrt[125]{e^{102}}$$
The amount of money in the account after 17 years is approximately $24,876.80.

Rounded to the nearest ten dollars, the amount of money in the account after 17 years is $24,880.
After 17 years, Khloe will have approximately \$24,880 in her account.

Khloe invested in an account paying an interest rate of compounded continuously.
Assuming no deposits or withdrawals are made, how much money, to the nearest ten dollars, would be
in the account after 17 years?

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Khloe invested in an account paying an interest rate of compounded continuously. Assuming no deposits or withdrawals are made, how much money, to the nearest ten dollars, would be in the account after 17 years?