4. A straight line has equation $$ x+y=5 $$. (i) By substituting $$ x=0 $$, find the coordinates of the point where the line crosses the $$ y $$-axis. (ii) By substituting $$ y=0 $$, find the coordinates of the point where the line crosses the $$ x $$-axis. (iii) Draw a graph of the line $$ x+y=5 $$.

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**(i) Finding the $$ y $$-axis intercept:**

Substitute $$ x=0 $$ into the equation:
$$
0 + y = 5 \quad \Rightarrow \quad y = 5.
$$
Thus, the line crosses the $$ y $$-axis at $$ (0,5) $$.

**(ii) Finding the $$ x $$-axis intercept:**

Substitute $$ y=0 $$ into the equation:
$$
x + 0 = 5 \quad \Rightarrow \quad x = 5.
$$
Thus, the line crosses the $$ x $$-axis at $$ (5,0) $$.

**(iii) Drawing the graph of $$ x+y=5 $$:**

1. Plot the point $$ (0,5) $$ on the $$ y $$-axis.
2. Plot the point $$ (5,0) $$ on the $$ x $$-axis.
3. Draw a straight line through these two points to represent the line $$ x+y=5 $$.

The two intercepts $$ (0,5) $$ and $$ (5,0) $$ determine the line completely.
**(i) The line crosses the $$ y $$-axis at $$ (0,5) $$.** **(ii) The line crosses the $$ x $$-axis at $$ (5,0) $$.** **(iii) Draw a straight line through the points $$ (0,5) $$ and $$ (5,0) $$ to graph $$ x+y=5 $$.

A straight line has equation .
(i) By substituting , find the coordinates of the point where the line crosses the
-axis.
(ii) By substituting , find the coordinates of the point where the line crosses the
-axis.
(iii) Draw a graph of the line .

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A straight line has equation . (i) By substituting , find the coordinates of the point where the line crosses the -axis. (ii) By substituting , find the coordinates of the point where the line crosses the -axis. (iii) Draw a graph of the line .