To measure the height of the cloud cover at an airport, a worker shines a spotlight upward at an angle of \( 80^{\circ} \) from the horizontal. An observer 732 m away measures the angle of elevation to the spot of light to be \( 49^{\circ} \). Find the height of the cloud cover. height = Report answer accurate to 2 decimal places.

Given: - The angle of elevation from the horizontal to the spotlight is \( 80^{\circ} \). - The angle of elevation from the observer to the spotlight is \( 49^{\circ} \). - The distance from the observer to the spotlight is 732 m. We can use trigonometry to find the height of the cloud cover. Let's denote the height of the cloud cover as \( h \). From the given information, we can form a right-angled triangle with the spotlight as the vertex opposite the angle of elevation from the observer. The distance from the observer to the spotlight is the adjacent side, and the height of the cloud cover is the opposite side. Using the tangent function, we can relate the angle of elevation, the height of the cloud cover, and the distance from the observer to the spotlight: \[ \tan(49^{\circ}) = \frac{h}{732} \] Now, we can solve for \( h \) by rearranging the equation: \[ h = 732 \times \tan(49^{\circ}) \] Let's calculate the height of the cloud cover using the tangent function. The height of the cloud cover is approximately 2322.57 m. Therefore, the height of the cloud cover is approximately 2322.57 m.