Solve the equation for $$ w $$. $$ 4 w^{2}+23 w+28=0 $$

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Solve the equation $$ 4w^{2}+23w+28=0 $$.
Solve the quadratic equation by following steps:
- step0: Solve by factoring:
  $$4w^{2}+23w+28=0$$
- step1: Factor the expression:
  $$\left(w+4ight)\left(4w+7ight)=0$$
- step2: Separate into possible cases:
  $$\begin{align}&4w+7=0\&w+4=0\end{align}$$
- step3: Solve the equation:
  $$\begin{align}&w=-\frac{7}{4}\&w=-4\end{align}$$
- step4: Rewrite:
  $$w_{1}=-4,w_{2}=-\frac{7}{4}$$
The solutions to the equation $$4w^{2}+23w+28=0$$ are $$w=-4$$ and $$w=-\frac{7}{4}$$ or $$w=-1.75$$.
$$ w=-4 $$ or $$ w=-1.75 $$.

Solve the equation for .

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