4)) $$ \left.{ }^{\frac{1}{x}}\right]_{j} $$ Simplify. Assume $$ b $$ is greater than or equal to zero. $$ \sqrt{75 b^{3}} $$

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Calculate or simplify the expression $$ \sqrt{75b^3} $$.
Simplify the expression by following steps:
- step0: Solution:
  $$\sqrt{75b^{3}}$$
- step1: Write as a product:
  $$\sqrt{25	imes 3b^{3}}$$
- step2: Write in exponential form:
  $$\sqrt{5^{2}	imes 3b^{3}}$$
- step3: Rewrite the exponent:
  $$\sqrt{5^{2}	imes 3b^{2+1}}$$
- step4: Expand the expression:
  $$\sqrt{5^{2}	imes 3b^{2}	imes b}$$
- step5: Reorder the terms:
  $$\sqrt{5^{2}b^{2}	imes 3b}$$
- step6: Use the properties of radicals:
  $$\sqrt{5^{2}b^{2}}	imes \sqrt{3b}$$
- step7: Simplify the root:
  $$5b\sqrt{3b}$$
The simplified form of $$ \sqrt{75b^3} $$ is $$ 5b\sqrt{3b} $$.
$$ \sqrt{75b^3} = 5b\sqrt{3b} $$

4)) Simplify. Assume is greater than or equal to zero.

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