Suppose that $$ g(x)=2^{x}+1 $$. (a) What is $$ g(-1) $$ ? When $$ x=-1 $$, what is the point on the graph of $$ g $$ ? (b) If $$ g(x)=9 $$, what is $$ x $$ ? When $$ g(x)=9 $$, what is the point on the graph of $$ g $$ ? (a) $$ g(-1)=\square $$. The point $$ \square $$ is on the graph of $$ g $$. (Type integers or simplified fractions.)

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**(a)**  
We are given $$ g(x)=2^x+1 $$. To compute $$ g(-1) $$, substitute $$ x = -1 $$ into the function:

$$
g(-1)=2^{-1}+1=\frac{1}{2}+1=\frac{3}{2}.
$$

The point on the graph corresponding to $$ x=-1 $$ is

$$
\left(-1, \frac{3}{2}\right).
$$

**(b)**  
We are given $$ g(x)=2^x+1 $$ and need to find $$ x $$ such that

$$
g(x)=9.
$$

Set up the equation:

$$
2^x+1=9.
$$

Subtract 1 from both sides:

$$
2^x=8.
$$

Since $$ 8=2^3 $$, we have

$$
2^x=2^3.
$$

Thus, the exponents must be equal:

$$
x=3.
$$

The point on the graph corresponding to $$ g(x)=9 $$ is

$$
(3, 9).
$$

**Answers:**  
(a) $$ g(-1)=\frac{3}{2} $$. The point $$ \left(-1, \frac{3}{2}\right) $$ is on the graph of $$ g $$.  
(b) $$ x=3 $$. The point $$ (3, 9) $$ is on the graph of $$ g $$.
**(a)** $$ g(-1) = \frac{3}{2} $$. The point $$ \left(-1, \frac{3}{2}\right) $$ is on the graph of $$ g $$. **(b)** $$ x = 3 $$. The point $$ (3, 9) $$ is on the graph of $$ g $$.

Suppose that .
(a) What is ? When , what is the point on the graph of ?
(b) If , what is ? When , what is the point on the graph of ?
(a) . The point is on the graph of .
(Type integers or simplified fractions.)

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Suppose that . (a) What is ? When , what is the point on the graph of ? (b) If , what is ? When , what is the point on the graph of ? (a) . The point is on the graph of . (Type integers or simplified fractions.)