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The graph shifts 2 units to the left, moving the vertex from (0,0) to (-2,0).
Solución
When altering the quadratic function from \( y = x^2 \) to \( y = (x + 2)^2 \), the graph undergoes a horizontal shift. Here's a detailed breakdown of the changes:
1. **Horizontal Shift:**
- **Direction:** The graph shifts **2 units to the left**.
- **Reason:** The equation \( y = (x + 2)^2 \) can be rewritten as \( y = (x - (-2))^2 \), indicating a horizontal shift of \( -2 \) units (left) from the original graph.
2. **Vertex Movement:**
- **Original Vertex:** For \( y = x^2 \), the vertex is at the origin \( (0, 0) \).
- **New Vertex:** After the shift, the vertex moves to \( (-2, 0) \).
3. **Axis of Symmetry:**
- **Original Axis:** The axis of symmetry for \( y = x^2 \) is the vertical line \( x = 0 \).
- **New Axis:** For \( y = (x + 2)^2 \), the axis of symmetry shifts to \( x = -2 \).
4. **Shape and Orientation:**
- **Same Shape:** The parabola retains its **U-shape** and **width**; there is no vertical stretching, compression, or reflection.
- **Opening Direction:** It continues to **open upwards**, just like the original graph.
5. **Key Points:**
- **No Vertical Shift:** There's no change in the \( y \)-values; only the \( x \)-values are affected.
- **Example Point Transformation:** A point \( (a, b) \) on \( y = x^2 \) moves to \( (a - 2, b) \) on \( y = (x + 2)^2 \).
**Visual Illustration:**
- **Original Graph (\( y = x^2 \)):**
- Vertex at \( (0, 0) \)
- Passes through points like \( (1, 1) \) and \( (-1, 1) \)
- **Shifted Graph (\( y = (x + 2)^2 \)):**
- Vertex at \( (-2, 0) \)
- Passes through points like \( (-1, 1) \) and \( (-3, 1) \)
**Conclusion:**
Changing the equation from \( y = x^2 \) to \( y = (x + 2)^2 \) results in the entire parabola shifting **2 units to the left** on the Cartesian plane, with the vertex moving from the origin to the point \( (-2, 0) \). The overall shape and orientation of the graph remain unchanged.
Revisado y aprobado por el equipo de tutoría de UpStudy
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