What is the first derivative of $$ q(x)=-3\left(e^{x}\right)^{3} ? $$

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To find the first derivative of the function $$ q(x) = -3\left(e^{x}\right)^{3} $$, follow these steps:

1. **Simplify the Function:**
   
   The given function can be rewritten using the properties of exponents:
   $$
   q(x) = -3\left(e^{x}\right)^{3} = -3e^{3x}
   $$

2. **Differentiate Using the Chain Rule:**

The derivative of $$ e^{3x} $$ with respect to $$ x $$ is $$ 3e^{3x} $$. Apply the constant multiple rule as well:
   $$
   \frac{dq}{dx} = -3 \cdot \frac{d}{dx}\left(e^{3x}\right) = -3 \cdot 3e^{3x} = -9e^{3x}
   $$

3. **Final Answer:**
   
   Therefore, the first derivative of $$ q(x) $$ is:
   $$
   q'(x) = -9e^{3x}
   $$

**Answer:**  
After simplifying, the first derivative is –9 multiplied by e³ˣ. Thus,

q ′ (x) = −9 e^{3x}
The first derivative of $$ q(x) = -3e^{3x} $$ is $$ q'(x) = -9e^{3x} $$.

What is the first derivative of

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