Ures of Variation According to a random sample taken at 12 A.M., body temperatures of healthy adults have a bell-shaped distribution with a mean of \( 98.08^{\circ} \mathrm{F} \) and a standard deviation of \( 0.59^{\circ} \mathrm{F} \). Using Chebysher/s do we know about the percentage of healthy adults with body temperatures that are within 2 standard deviations of the mean? What are the minimum and maximum possible body temperatures that standard deviations of the mean? H. \( 9.2 .44,5.17 \) of 11 points At least \( \square \% \) of healthy adults have body temperatures within 2 standard deviations of \( 98.08^{\circ} \mathrm{F} \). (Round to the nearest percent as needed.)
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Chebyshev's theorem tells us that no less than \( \frac{1}{k^2} \) of data points will fall within \( k \) standard deviations of the mean, regardless of the data's distribution shape. For \( k = 2 \) standard deviations, this means that at least \( \frac{1}{2^2} = \frac{1}{4} \) or 25% of data points will be within 2 standard deviations of the mean. In the case of body temperatures, this implies at least 75% of healthy adults have body temperatures within this range. To find the minimum and maximum possible body temperatures, we take the mean and add/subtract two times the standard deviation: - Minimum: \( 98.08 - 2 \times 0.59 = 96.90^\circ F \) - Maximum: \( 98.08 + 2 \times 0.59 = 99.26^\circ F \) So, healthy adult body temperatures range from \( 96.90^\circ F \) to \( 99.26^\circ F \).