Pregunta
Find the first five partial sums of the given series and determine whether the series appears to be
convergent or divergent. If it is convergent, find its approximate sum.
The first partial sum is
.
(Type an integer or decimal rounded to four decimal places as needed.)
The second partial sum is
(Type an integer or decimal rounded to four decimal places as needed.)
Find the first five partial sums of the given series and determine whether the series appears to be |
convergent or divergent. If it is convergent, find its approximate sum. |
The first partial sum is
|
(Type an integer or decimal rounded to four decimal places as needed.) |
The second partial sum is
|
(Type an integer or decimal rounded to four decimal places as needed.) |
|
Ask by Chandler Cruz. in the United States
Jan 12,2025
Solución de inteligencia artificial de Upstudy
Respuesta verificada por el tutor
Responder
The first five partial sums are:
The series converges to 1.
Solución

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Como
Beyond the Answer
To analyze the convergence of the series and find the partial sums, let’s first clarify the series in question based on your notation.
Assuming the series is defined as follows:
We can find the first few partial sums step by step.
-
The first partial sum is given:
. -
For the second partial sum:
Now, let’s find the next three partial sums.
-
For the third partial sum:
-
For the fourth partial sum:
-
For the fifth partial sum:
The partial sums calculated are approximately:
As the sequence of partial sums seems to be stabilizing around a specific number (as it continues to rise but at a decreasing rate), it suggests that the series may be convergent.
To determine if the series converges, recall the convergence of such series can at times be bound by a limit as
approaches infinity. In this case, using the formula for the general term in partial fraction decomposition may help indicate that the series converges and leads to finding its sum.
So, it’s quite likely that the series converges, and rounding the approximate sum gives us a value around
.
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