O. $$ 3 \frac{2}{8} imes 1 \frac{1}{4}= $$ E. $$ 5 \frac{2}{4} imes 1 \frac{1}{3}= $$ Y. $$ 1 \frac{1}{2} imes 3 \frac{1}{6}= $$ P. $$ 1 \frac{2}{6} imes 3 \frac{1}{4}= $$

Question

O. $$ 3 \frac{2}{8} 	imes 1 \frac{1}{4}= $$ E. $$ 5 \frac{2}{4} 	imes 1 \frac{1}{3}= $$ Y. $$ 1 \frac{1}{2} 	imes 3 \frac{1}{6}= $$ P. $$ 1 \frac{2}{6} 	imes 3 \frac{1}{4}= $$

UpStudy AI · Accepted Answer

**Problem O: $$3 \frac{2}{8} \times 1 \frac{1}{4}$$**

1. Simplify the mixed number:
   - $$3 \frac{2}{8}$$ simplifies because $$\frac{2}{8} = \frac{1}{4}$$, so it becomes $$3 \frac{1}{4}$$.

2. Convert the mixed numbers to improper fractions:
   - $$3 \frac{1}{4} = \frac{3 \times 4 + 1}{4} = \frac{13}{4}$$
   - $$1 \frac{1}{4} = \frac{1 \times 4 + 1}{4} = \frac{5}{4}$$

3. Multiply the improper fractions:
   $$
   \frac{13}{4} \times \frac{5}{4} = \frac{65}{16}
   $$

4. Convert the result to a mixed number:
   - Divide $$65$$ by $$16$$: $$16 \times 4 = 64$$ with a remainder of $$1$$.
   $$
   \frac{65}{16} = 4 \frac{1}{16}
   $$

**Answer O: $$4 \frac{1}{16}$$**

---

**Problem E: $$5 \frac{2}{4} \times 1 \frac{1}{3}$$**

1. Simplify the mixed number:
   - $$5 \frac{2}{4}$$ simplifies because $$\frac{2}{4} = \frac{1}{2}$$, so it becomes $$5 \frac{1}{2}$$.

2. Convert the mixed numbers to improper fractions:
   - $$5 \frac{1}{2} = \frac{5 \times 2 + 1}{2} = \frac{11}{2}$$
   - $$1 \frac{1}{3} = \frac{1 \times 3 + 1}{3} = \frac{4}{3}$$

3. Multiply the improper fractions:
   $$
   \frac{11}{2} \times \frac{4}{3} = \frac{44}{6}
   $$

4. Simplify the fraction:
   - Divide numerator and denominator by $$2$$:
   $$
   \frac{44}{6} = \frac{22}{3}
   $$

5. Convert the result to a mixed number:
   - Divide $$22$$ by $$3$$: $$3 \times 7 = 21$$ with a remainder of $$1$$.
   $$
   \frac{22}{3} = 7 \frac{1}{3}
   $$

**Answer E: $$7 \frac{1}{3}$$**

---

**Problem Y: $$1 \frac{1}{2} \times 3 \frac{1}{6}$$**

1. Convert the mixed numbers to improper fractions:
   - $$1 \frac{1}{2} = \frac{1 \times 2 + 1}{2} = \frac{3}{2}$$
   - $$3 \frac{1}{6} = \frac{3 \times 6 + 1}{6} = \frac{19}{6}$$

2. Multiply the improper fractions:
   $$
   \frac{3}{2} \times \frac{19}{6} = \frac{57}{12}
   $$

3. Simplify the fraction:
   - Divide numerator and denominator by $$3$$:
   $$
   \frac{57}{12} = \frac{19}{4}
   $$

4. Convert the result to a mixed number:
   - Divide $$19$$ by $$4$$: $$4 \times 4 = 16$$ with a remainder of $$3$$.
   $$
   \frac{19}{4} = 4 \frac{3}{4}
   $$

**Answer Y: $$4 \frac{3}{4}$$**

---

**Problem P: $$1 \frac{2}{6} \times 3 \frac{1}{4}$$**

1. Simplify the mixed number:
   - $$1 \frac{2}{6}$$ simplifies because $$\frac{2}{6} = \frac{1}{3}$$, so it becomes $$1 \frac{1}{3}$$.

2. Convert the mixed numbers to improper fractions:
   - $$1 \frac{1}{3} = \frac{1 \times 3 + 1}{3} = \frac{4}{3}$$
   - $$3 \frac{1}{4} = \frac{3 \times 4 + 1}{4} = \frac{13}{4}$$

3. Multiply the improper fractions:
   $$
   \frac{4}{3} \times \frac{13}{4} = \frac{52}{12}
   $$

4. Simplify the fraction:
   - Cancel the common factor $$4$$ in the numerator and denominator:
   $$
   \frac{52}{12} = \frac{13}{3}
   $$

5. Convert the result to a mixed number:
   - Divide $$13$$ by $$3$$: $$3 \times 4 = 12$$ with a remainder of $$1$$.
   $$
   \frac{13}{3} = 4 \frac{1}{3}
   $$

**Answer P: $$4 \frac{1}{3}$$**
**Solutions:** - **O:** $$4 \frac{1}{16}$$ - **E:** $$7 \frac{1}{3}$$ - **Y:** $$4 \frac{3}{4}$$ - **P:** $$4 \frac{1}{3}$$

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