(1 point) Evaluate the indefinite integral $$ \int\left(\frac{1}{x^{6}}+\frac{16}{15 x}\right) d x $$ \begin{tabular}{l}$$ \square:+ $$ \ \hline\end{tabular}

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Let us evaluate the integral step by step.

1. Write the integral as a sum of two integrals:
$$
\int \left(\frac{1}{x^6}+\frac{16}{15x}\right)dx = \int x^{-6}dx + \frac{16}{15} \int \frac{1}{x}dx.
$$

2. Evaluate the first integral using the power rule $$ \int x^n dx = \frac{x^{n+1}}{n+1} $$ (for $$ n \neq -1 $$):
$$
\int x^{-6}dx = \frac{x^{-5}}{-5} = -\frac{1}{5x^5}.
$$

3. Evaluate the second integral:
$$
\frac{16}{15} \int \frac{1}{x}dx = \frac{16}{15}\ln|x|.
$$

4. Combine the two results:
$$
-\frac{1}{5x^5} + \frac{16}{15}\ln|x| + C.
$$

Thus, the indefinite integral is:
$$
-\frac{1}{5x^5} + \frac{16}{15}\ln|x| + C.
$$
The indefinite integral is $$ -\frac{1}{5x^5} + \frac{16}{15}\ln|x| + C $$.

(1 point) Evaluate the indefinite integral

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