(a) The masses of 2 bags of sugar, \( A \) and \( B \), are 750 g and \( 1 \frac{1}{3} \mathrm{~kg} \) respectively. Find the ratio of the mass of \( B \) to the mass of \( A \).

To find the ratio of the mass of bag \( B \) to the mass of bag \( A \), follow these steps: 1. **Convert Masses to the Same Unit:** - **Bag \( A \):** \( 750 \) grams (g) - **Bag \( B \):** \( 1 \frac{1}{3} \) kilograms (kg) Since \( 1 \) kg \( = 1000 \) grams, convert the mass of bag \( B \) to grams: \[ 1 \frac{1}{3} \, \text{kg} = \frac{4}{3} \, \text{kg} = \frac{4}{3} \times 1000 \, \text{g} = 1333 \frac{1}{3} \, \text{g} \] 2. **Set Up the Ratio:** \[ \text{Ratio of } B \text{ to } A = \frac{\text{Mass of } B}{\text{Mass of } A} = \frac{1333 \frac{1}{3} \, \text{g}}{750 \, \text{g}} \] 3. **Simplify the Ratio:** Convert the mixed number to an improper fraction: \[ \frac{1333 \frac{1}{3}}{750} = \frac{\frac{4000}{3}}{750} = \frac{4000}{2250} \] Simplify by dividing both numerator and denominator by 250: \[ \frac{4000 \div 250}{2250 \div 250} = \frac{16}{9} \] 4. **Express the Ratio:** The simplified ratio of the mass of \( B \) to \( A \) is: \[ 16 : 9 \] **Answer:** The ratio of the mass of B to A is 16 to 9, that is 16 : 9.