(a) The masses of 2 bags of sugar, $$ A $$ and $$ B $$, are 750 g and $$ 1 \frac{1}{3} \mathrm{~kg} $$ respectively. Find the ratio of the mass of $$ B $$ to the mass of $$ A $$.

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To find the ratio of the mass of bag $$ B $$ to the mass of bag $$ A $$, follow these steps:

1. **Convert Masses to the Same Unit:**
   
   - **Bag $$ A $$:** $$ 750 $$ grams (g)
   - **Bag $$ B $$:** $$ 1 \frac{1}{3} $$ kilograms (kg)
   
   Since $$ 1 $$ kg $$ = 1000 $$ grams, convert the mass of bag $$ B $$ to grams:
   
   $$
   1 \frac{1}{3} \, \text{kg} = \frac{4}{3} \, \text{kg} = \frac{4}{3} \times 1000 \, \text{g} = 1333 \frac{1}{3} \, \text{g}
   $$

2. **Set Up the Ratio:**

$$
   \text{Ratio of } B \text{ to } A = \frac{\text{Mass of } B}{\text{Mass of } A} = \frac{1333 \frac{1}{3} \, \text{g}}{750 \, \text{g}}
   $$

3. **Simplify the Ratio:**

Convert the mixed number to an improper fraction:

$$
   \frac{1333 \frac{1}{3}}{750} = \frac{\frac{4000}{3}}{750} = \frac{4000}{2250}
   $$

Simplify by dividing both numerator and denominator by 250:

$$
   \frac{4000 \div 250}{2250 \div 250} = \frac{16}{9}
   $$

4. **Express the Ratio:**

The simplified ratio of the mass of $$ B $$ to $$ A $$ is:

$$
   16 : 9
   $$

**Answer:** The ratio of the mass of B to A is 16 to 9, that is 16 : 9.
The ratio of the mass of bag B to bag A is 16:9.

(a) The masses of 2 bags of sugar, and , are 750 g and respectively.
Find the ratio of the mass of to the mass of .

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(a) The masses of 2 bags of sugar, and , are 750 g and respectively. Find the ratio of the mass of to the mass of .