5 Ed has two dogs. The smaller dog weighs \( 8 \frac{1}{3} \) pounds. The larger dog weighs \( 1 \frac{1}{2} \) time as much as the smaller dog. How much do the larger dog weigh?

To find the weight of the larger dog, first convert the mixed numbers into improper fractions. The smaller dog weighs \( 8 \frac{1}{3} \) pounds, which can be expressed as \(\frac{25}{3}\) pounds. The larger dog weighs \( 1 \frac{1}{2} \) times as much as the smaller dog, or \( \frac{3}{2} \times \frac{25}{3} = \frac{75}{6} \). Simplifying \(\frac{75}{6}\) gives us \( 12 \frac{1}{2} \) pounds. So, the larger dog weighs \( 12 \frac{1}{2} \) pounds!