Pregunta
1 Keith opened a savings account with \( \$ 400 \) and was paid simple interest at an annual rate of \( 4 \% \). When Keith closed the account, he was paid \( \$ 64 \) in in How long was the account open for, in years? If necessary, refer to the list of financial formulas.
Ask by Nunez Powers. in the United States
Feb 03,2025
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Keith's account was open for 4 years.
Solución
To determine how long Keith's savings account was open, we'll use the **simple interest formula**:
\[
\text{Interest} (I) = \text{Principal} (P) \times \text{Rate} (r) \times \text{Time} (t)
\]
**Given:**
- **Principal (P):** \$400
- **Annual Interest Rate (r):** 4% or 0.04 (in decimal)
- **Interest Earned (I):** \$64
**Plugging the values into the formula:**
\[
64 = 400 \times 0.04 \times t
\]
**Calculate the product of Principal and Rate:**
\[
400 \times 0.04 = 16
\]
So, the equation simplifies to:
\[
64 = 16 \times t
\]
**Solve for Time (t):**
\[
t = \frac{64}{16} = 4 \text{ years}
\]
**Answer:**
Keith's account was open for **4 years**.
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The Deep Dive
To find out how long the account was open, we can use the formula for simple interest: \[ I = P \times r \times t \] Where: - \( I \) is the interest earned (\$64), - \( P \) is the principal amount (\$400), - \( r \) is the annual interest rate (4%, or 0.04 as a decimal), - \( t \) is the time in years. Now, we can rearrange the formula to solve for \( t \): \[ t = \frac{I}{P \times r} \] Plugging in the values: \[ t = \frac{64}{400 \times 0.04} = \frac{64}{16} = 4 \] So, the account was open for 4 years.
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