() $$ y=4320(1.038)^{t} $$ Explain Find the number of jiu-jitsu instructors in 2006. Give your answer to the nearest whole number. $$ = $$ $$ \square $$ Enter your next step here

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We are given the exponential model

$$
y = 4320(1.038)^{t},
$$

where $$ y $$ represents the number of jiu-jitsu instructors and $$ t $$ represents the number of years after the base year. If we assume that the model starts at $$ t=0 $$ in the year 2000, then for the year 2006 we have

$$
t = 2006 - 2000 = 6.
$$

Now, substitute $$ t=6 $$ into the equation:

$$
y = 4320(1.038)^6.
$$

The next step is to evaluate $$ (1.038)^6 $$:

- Using a calculator or an appropriate method, we compute
  $$
  (1.038)^6 \approx 1.25194.
  $$

Then, multiply this value by 4320:

$$
y \approx 4320 \times 1.25194 \approx 5408.38.
$$

Since we are asked to give the answer to the nearest whole number, we round:

$$
y \approx 5408.
$$

Thus, the number of jiu-jitsu instructors in 2006 is approximately $$\boxed{5408}$$.
The number of jiu-jitsu instructors in 2006 is approximately 5,408.

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Find the number of jiu-jitsu instructors in 2006. Give your answer to the nearest whole number.
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Find the number of jiu-jitsu instructors in 2006. Give your answer to the nearest whole number. [