Find the product $$ \left(6 x^{2}-7\right)\left(5 x^{2}-6\right) $$ $$ \left(6 x^{2}-7\right)\left(5 x^{2}-6\right)=\square $$ (Simplify your answer.)

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Calculate or simplify the expression $$ (6*x^2-7)*(5*x^2-6) $$.
Simplify the expression by following steps:
- step0: Solution:
  $$\left(6x^{2}-7ight)\left(5x^{2}-6ight)$$
- step1: Apply the distributive property:
  $$6x^{2}	imes 5x^{2}-6x^{2}	imes 6-7	imes 5x^{2}-\left(-7	imes 6ight)$$
- step2: Multiply the terms:
  $$30x^{4}-36x^{2}-35x^{2}-\left(-42ight)$$
- step3: Remove the parentheses:
  $$30x^{4}-36x^{2}-35x^{2}+42$$
- step4: Subtract the terms:
  $$30x^{4}-71x^{2}+42$$
The product $$(6x^{2}-7)(5x^{2}-6)$$ simplifies to $$30x^{4}-71x^{2}+42$$.
$$30x^{4}-71x^{2}+42$$

Find the product

(Simplify your answer.)

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