esystem \( y=4 x-3 \) and \( y=4 x+3 \)

Solve the system of equations \( y=4x-3;y=4x+3 \). Solve the system of equations by following steps: - step0: Solve using the substitution method: \(\left\{ \begin{array}{l}y=4x-3\\y=4x+3\end{array}\right.\) - step1: Substitute the value of \(y:\) \(4x-3=4x+3\) - step2: Cancel equal terms: \(-3=3\) - step3: The statement is false: \(x \in \varnothing \) - step4: Calculate: \(\left\{ \begin{array}{l}x \in \varnothing \\y \in \varnothing \end{array}\right.\) - step5: Rewrite: \((x, y) \in \varnothing\) The system of equations \(y=4x-3\) and \(y=4x+3\) has no solution. This means that there is no point that satisfies both equations simultaneously.