Which of the following values are solutions to the inequality \( -2 \leq 9-4 x \) ? \[ \begin{array}{lll}\text { I. } 10 & \text { II. }-4 & \text { III. } 6\end{array} \]
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To solve the inequality \( -2 \leq 9 - 4x \), we can first isolate \( x \). Start by subtracting 9 from both sides: \[ -2 - 9 \leq -4x \] This simplifies to: \[ -11 \leq -4x \] Next, divide both sides by -4 (remembering to flip the inequality sign when dividing by a negative): \[ \frac{-11}{-4} \geq x \] This simplifies to: \[ \frac{11}{4} \geq x \] or \[ x \leq \frac{11}{4} \] Now, we need to check which of the given values satisfy this condition: 1. For \( x = 10 \): \( 10 \) is greater than \( \frac{11}{4} \) (approximately \( 2.75 \)), so it does not satisfy \( x \leq \frac{11}{4} \). 2. For \( x = -4 \): \( -4 \) is less than \( \frac{11}{4} \), so it satisfies \( x \leq \frac{11}{4} \). 3. For \( x = 6 \): \( 6 \) is greater than \( \frac{11}{4} \), so it does not satisfy \( x \leq \frac{11}{4} \). Thus, the only solution is: **II. -4**