Acceso
Prima
Hogar Banco de preguntas Matemáticas Álgebra
Pregunta
upstudy study bank question image url

A pre-paid cell phone company charges \( \$ 12.7 \) as a monthly access fee and \( \$ 0.13 \) per minute of calling time. Express the monthly cost \( C \) in terms of minutes of call time. What will the monthly cost be if you make 353 minutes of calls this month?

Ask by Harris Fernandez. in the United States
Feb 04,2025

Solución de tutoría real

Respuesta verificada por el tutor

Responder

The monthly cost \( C \) is calculated as \( C = 12.7 + 0.13m \), where \( m \) is the number of minutes. For 353 minutes, the cost is \$58.59.

Solución

¡Inicia sesión para desbloquear respuestas gratis!

Una plataforma de aprendizaje en la que confían millones de estudiantes y profesores reales.

star-icon Descubrir

Revisado y aprobado por el equipo de tutoría de UpStudy

Extra Insights

The monthly cost \( C \) can be expressed as a function of the minutes of call time \( m \) as follows: \[ C(m) = 12.7 + 0.13m \] This equation includes the fixed monthly access fee of \( \$12.7 \) and adds \( \$0.13 \) for each minute used. To calculate the monthly cost for 353 minutes, plug in \( m = 353 \): \[ C(353) = 12.7 + 0.13 \times 353 \] \[ C(353) = 12.7 + 45.89 = 58.59 \] Thus, the total monthly cost for making 353 minutes of calls is \( \$58.59 \).

preguntas relacionadas

\begin{tabular}{l} Which expression is equivalent to \( 4 x^{-2}+3 x^{-5} \) ? \\ A. \( 7 x^{-7} \) \\ B. \( 12 x^{10} \) \\ C. \( \frac{7}{x^{7}} \) \\ D. \( \frac{4 x^{3}+3}{x^{5}} \) \\ E. \( \frac{4 x^{5}+3}{x^{7}} \) \\ \hline\end{tabular}
Álgebra United Arab Emirates Feb 04, 2025
(a) Consider the following system of linear equations: \[ \begin{aligned} 5 x_{1}+4 x_{2}+17 x_{3} & =3 \\ -4 x_{1}+4 x_{2}-7 x_{3} & =6 \\ x_{1}+x_{3} & =-5 \end{aligned} \] (i) Write down matrix \( A \) and vector \( b \), where \( A x=b \). Apply the \( L U \) decomposition technique on \( A \). Find the elementary matrices \( E_{i j} \). ( 10 marks) (ii) Based on the \( L U \) decomposition of \( A \), solve the system of linear equations. ( 5 marks) (iii) Use the \( L U \) decomposition of \( A \) to find the first column of \( A^{-1} \). (b) Consider the following system of linear equations: (5 marks) \[ \begin{array}{r} -2 x_{1}+8 x_{2}+4 x_{3}=5 \\ 4 x_{1}-3 x_{2}+8 x_{3}=6 \\ 6 x_{1}-2 x_{2}+3 x_{3}=-1 \end{array} \] Apply the conditions for a set of linear equations. Starting from \( \left(x_{1}, x_{2}, x_{3}\right)= \) \( (-1,0,1) \), perform three iterations of the Gauss-Seidel iterative scheme. Keep all values up to five decimal places. Provide enough details fof the iterative process.
Álgebra Singapore Feb 04, 2025
Expand \( \left(\frac{2 a}{3}-\frac{b^{2}}{4}\right)^{3} \)
Álgebra India Feb 04, 2025
19.6. \( x^{2}-2 x+1=0 \)
Álgebra Portugal Feb 04, 2025
\( 04 / 02 / 2025 \) Exponents and surds Classwork Simplify the following expressions and leave answer with positive exponents. \[ \begin{array}{l} \text { 1. } 4 x^{9} \cdot 2 x^{-6} \\ 24^{n-1} \times 4^{1-n} \times 4^{2} \\ \text { 3 } \frac{9 x^{3} x^{2}}{1 \cdot x y^{4}} \\ \text { 4. }\left(3 x^{-3} \cdot y^{4}\right)^{-2} \\ \text { 5. } \left.2(x)^{-2}\right)^{3} \\ 6\left(\frac{x^{-1}}{y^{-1}}\right)^{-2} \\ \text { 1. } \left.\frac{2}{m^{2}}\right)^{-3} \\ \text { 8. } \frac{x^{\frac{3}{3}} \times x^{3}}{(x)^{4}} \\ \text { 9. } \frac{27 x^{-3} y^{-2}}{81 x^{2} y^{-3}} \\ \text { 10. } \frac{m^{3} n^{-6}}{m^{-4} n^{-1}} \times \frac{m^{-2} \cdot n^{4}}{m^{3} n^{4}} \end{array} \]
Álgebra South Africa Feb 04, 2025

Latest Algebra Questions

\( 04 / 02 / 2025 \) Exponents and surds Classwork Simplify the following expressions and leave answer with positive exponents. \[ \begin{array}{l} \text { 1. } 4 x^{9} \cdot 2 x^{-6} \\ 24^{n-1} \times 4^{1-n} \times 4^{2} \\ \text { 3 } \frac{9 x^{3} x^{2}}{1 \cdot x y^{4}} \\ \text { 4. }\left(3 x^{-3} \cdot y^{4}\right)^{-2} \\ \text { 5. } \left.2(x)^{-2}\right)^{3} \\ 6\left(\frac{x^{-1}}{y^{-1}}\right)^{-2} \\ \text { 1. } \left.\frac{2}{m^{2}}\right)^{-3} \\ \text { 8. } \frac{x^{\frac{3}{3}} \times x^{3}}{(x)^{4}} \\ \text { 9. } \frac{27 x^{-3} y^{-2}}{81 x^{2} y^{-3}} \\ \text { 10. } \frac{m^{3} n^{-6}}{m^{-4} n^{-1}} \times \frac{m^{-2} \cdot n^{4}}{m^{3} n^{4}} \end{array} \]
Álgebra South Africa Feb 04, 2025
\begin{tabular}{l} Which expression is equivalent to \( 4 x^{-2}+3 x^{-5} \) ? \\ A. \( 7 x^{-7} \) \\ B. \( 12 x^{10} \) \\ C. \( \frac{7}{x^{7}} \) \\ D. \( \frac{4 x^{3}+3}{x^{5}} \) \\ E. \( \frac{4 x^{5}+3}{x^{7}} \) \\ \hline\end{tabular}
Álgebra United Arab Emirates Feb 04, 2025
Which expression is equivalent to \( a^{1 / 3}+\frac{2}{a^{2 / 3}} \) ? A. \( \frac{a^{2 / 9}+2}{a^{2 / 3}} \) B. \( \frac{2}{a^{1 / 3}} \) C. \( \frac{a^{1 / 3}+2}{a^{2 / 3}} \) D. \( \frac{a+2}{a^{2 / 3}} \) E. \( \frac{a^{2 / 3}+2}{a} \)
Álgebra United Arab Emirates Feb 04, 2025
Expand \( \left(\frac{2 a}{3}-\frac{b^{2}}{4}\right)^{3} \)
Álgebra India Feb 04, 2025
Which expression is equivalent to " 4 times the sum of 3 and \( x \) "?
Álgebra United Arab Emirates Feb 04, 2025
Anterior Próximo
¡Prueba Premium ahora!
¡Prueba Premium y hazle a Thoth AI preguntas de matemáticas ilimitadas ahora!
Quizas mas tarde Hazte Premium
Estudiar puede ser una verdadera lucha
¿Por qué no estudiarlo en UpStudy?
Seleccione su plan a continuación
Prima

Puedes disfrutar

Empieza ahora
  • Explicaciones paso a paso
  • Tutores expertos en vivo 24/7
  • Número ilimitado de preguntas
  • Sin interrupciones
  • Acceso completo a Respuesta y Solución
  • Acceso completo al chat de PDF, al chat de UpStudy y al chat de navegación
Básico

Totalmente gratis pero limitado

  • Solución limitada
Bienvenido a ¡Estudia ahora!
Inicie sesión para continuar con el recorrido de Thoth AI Chat
Continuar con correo electrónico
O continuar con
Al hacer clic en "Iniciar sesión", acepta nuestros términos y condiciones. Términos de Uso & Política de privacidad