Simplify completely: $$ \frac{1+\frac{4}{x}}{1-\frac{16}{x^{2}}} $$

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Calculate or simplify the expression $$ (1+\frac{4}{x})/(1-\frac{16}{x^{2}}) $$.
Simplify the expression by following steps:
- step0: Solution:
  $$\frac{\left(1+\frac{4}{x}ight)}{\left(1-\frac{16}{x^{2}}ight)}$$
- step1: Remove the parentheses:
  $$\frac{1+\frac{4}{x}}{1-\frac{16}{x^{2}}}$$
- step2: Add the terms:
  $$\frac{\frac{x+4}{x}}{1-\frac{16}{x^{2}}}$$
- step3: Subtract the terms:
  $$\frac{\frac{x+4}{x}}{\frac{x^{2}-16}{x^{2}}}$$
- step4: Multiply by the reciprocal:
  $$\frac{x+4}{x}	imes \frac{x^{2}}{x^{2}-16}$$
- step5: Rewrite the expression:
  $$\frac{x+4}{x}	imes \frac{x^{2}}{\left(x+4ight)\left(x-4ight)}$$
- step6: Reduce the fraction:
  $$\frac{x}{x-4}$$
The simplified form of $$ \frac{1+\frac{4}{x}}{1-\frac{16}{x^{2}}} $$ is $$ \frac{x}{x-4} $$.
$$ \frac{x}{x-4} $$

Simplify completely:

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