\( \begin{array}{l}40 \text { Listen } \\ \text { What is the solution to the system of equations? } \\ \begin{array}{l}3 x+5 y=-3 \\ 4 x+10 y=-14\end{array}\end{array} \)

To find the solution to the system of equations, let's analyze the two equations given: 1. \(3x + 5y = -3\) 2. \(4x + 10y = -14\) Notice that the second equation can be simplified by dividing everything by 2, giving us \(2x + 5y = -7\). If we compare this with the first equation, we can multiply the first equation by 2: \(2(3x + 5y) = 2(-3)\) which simplifies to \(6x + 10y = -6\). Now we can see that both equations represent the same line when rearranged, which indicates that they are dependent. Therefore, the system has infinitely many solutions along this line. For any value of \(y\), we can derive a corresponding \(x\) using \(x = \frac{-3 - 5y}{3}\). So, the solution set can be expressed as \((x, y) = \left(\frac{-3 - 5y}{3}, y\right)\) for any real number \(y\).