What is the coefficient of hydrogen, $$ \mathrm{H}_{2} $$, when the following equation is balanced? $$ \begin{array}{ll}\mathrm{Al}+\mathrm{H}_{2} \mathrm{SO}_{4} \rightarrow \mathrm{Al}_{2}\left(\mathrm{SO}_{4}\right)_{3}+? \mathrm{H}_{2} \ \text { Submit Request Answer }\end{array} $$

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To balance the chemical equation:

$$
\mathrm{Al} + \mathrm{H}_{2}\mathrm{SO}_{4} \rightarrow \mathrm{Al}_{2}\left(\mathrm{SO}_{4}\right)_{3} + \mathrm{H}_{2}
$$

Let's assign coefficients to each compound:

$$
a\,\mathrm{Al} + b\,\mathrm{H}_{2}\mathrm{SO}_{4} \rightarrow c\,\mathrm{Al}_{2}\left(\mathrm{SO}_{4}\right)_{3} + d\,\mathrm{H}_{2}
$$

**Balancing each element:**

1. **Aluminum (Al):**
   $$
   a = 2c
   $$

2. **Sulfur (S):**
   $$
   b = 3c
   $$

3. **Oxygen (O):**
   $$
   4b = 12c \quad (\text{since each } \mathrm{SO}_{4} \text{ has 4 O atoms})
   $$
   This simplifies to $$ b = 3c $$, consistent with the sulfur balance.

4. **Hydrogen (H):**
   $$
   2b = 2d \implies b = d
   $$

**Choosing $$ c = 1 $$:**

- $$ a = 2 \times 1 = 2 $$
- $$ b = 3 \times 1 = 3 $$
- $$ d = 3 $$ (from $$ b = d $$)

**Balanced Equation:**

$$
2\,\mathrm{Al} + 3\,\mathrm{H}_{2}\mathrm{SO}_{4} \rightarrow \mathrm{Al}_{2}\left(\mathrm{SO}_{4}\right)_{3} + 3\,\mathrm{H}_{2}
$$

Thus, the coefficient of hydrogen gas ($$ \mathrm{H}_{2} $$) is **3**.

**Answer:**  
The coefficient of hydrogen gas $$ \mathrm{H}_{2} $$ is 3.
The coefficient of hydrogen gas $$ \mathrm{H}_{2} $$ is 3.

What is the coefficient of hydrogen, \( \mathrm{H}_{2} \), when the following equation is balanced? \[ \begin{array}{ll}\mathrm{Al}+\mathrm{H}_{2} \mathrm{SO}_{4} \rightarrow \mathrm{Al}_{2}\left(\mathrm{SO}_{4}\right)_{3}+? \mathrm{H}_{2} \\ \text { Submit Request Answer }\end{array} \]

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