Describe the transformation from \( v(x)=x^{3}+2 \) to \( q(x)=(0.25 x)^{3}+2 \). 1 point horizontal stretch by a factor of 0.25 horizontal compression by a factor of 4 horizontal stretch by a factor of 4 horizontal compression by a factor of 0.25

The transformation from \( v(x)=x^{3}+2 \) to \( q(x)=(0.25 x)^{3}+2 \) involves a horizontal compression by a factor of 4. This is because when you input \( 0.25 x \) into the function, it effectively speeds up how quickly the graph reaches its values compared to the original function. So, for every unit increase in \( x \), \( q(x) \) increases faster than \( v(x) \). In simpler terms, you can think of it like this: by replacing \( x \) with \( 0.25 x \), you are really saying that the function will achieve the same output values much quicker, hence, making the graph "squeeze" towards the y-axis. It's like hugging your friends tighter at a group photo!